concentration of a stock solution in mol L-1 = moles of solute ÷ volume of solution in litres c1 = n1 ÷ V1 The dilution equation (dilution formula or dilution expression) is: c1V1 = c2V2 The dilution equation (dilution formula or dilution expression) is: c1V1 = c2V2 Please do not block ads on this website. Dilution TechniqueDilution means to reduce the concentration of a solution.A solution can be diluted by adding solvent to a given volume of stock solution. In order to dilute a solution we need:
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So we now have an equation (expression or formula) to calculate the concentration of a solution after it has been diluted:
If we rearrange this equation (expression or formula) by multiplying both sides of the equation by V2 we get: c1V1 = c2V2 which simply means that the moles of solute transferred by pipette and placed in the volumetric flask (n1) equals the moles of solute present in the volumetric flask after more solvent was added during the dilution (n2).
This equation (formula or expression) is very useful because we can rearrange it find:
Do you understand this? Join AUS-e-TUTE! Take the test now! Calculate the new concentration in mol L-1 (molarity) if enough water is added to 100.00 mL of 0.25 mol L-1 sodium chloride solution to make up 1.5 L.
Calculate the volume of solution after dilution (V2 = (c1V1) ÷ c2)Calculate the volume in litres to which 500.00 mL of 0.020 mol L-1 copper sulfate solution must be diluted to make a new solution with a concentration of 0.0010 mol L-1.
Calculate the concentration in mol L-1 of solution before dilution c1 = (c2V2) ÷ V1Calculate the concentration of the undiluted CuSO4(aq) if 10.00 mL of this solution was used to make 100.00 mL of dilute solution with a concentration of 0.20 mol L-1.
Calculate the volume of the pipette used to dilute a solution (V2 = (c1V1) ÷ c2)Calculate the volume of the pipette in millilitres used to transfer a quantity of 0.15 mol L-1 CuSO4(aq) to a 250.00 mL volumetric flask made up with enough water to produce a solution with a concentration of 0.012 mol L-1.
Can you apply this? Join AUS-e-TUTE! Take the exam now! Chris the chemist requires two aqueous solutions of sodium carbonate, Na2CO3(aq), of different concentrations for an analytical procedure. Chris carefully weighs out 5.00 g of sodium carbonate and transfers this to a 500.00 mL volumetric flask, adding enough water to make the solution up to the mark. Then Chris uses a pipette to transfer 50.00 mL of this solution to a 250.00 mL volumetric flask, adding enough water to make the solution up to the mark. Solving the Problem Using the StoPGoPS model for problem solving:
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