What is the concentration of a solution containing 1.0 g of sodium hydroxide?

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  1. 0.025mol/dm3
  2. 0.10mol/dm3
  3. 0.25mol/dm3
  4. 1.0mol/dm3

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A SOLUTION CONTAINS 1 GRAM OF SODIUM HYDROXIDE IN 250CM^3 OF SOLUTION.CALCULATE THE CONCENTRATION OF THE SOLUTION IN MOLDM^-3?

In Chemistry 2 Answers Available

Asked by mercy adeyanju on 4th July, 2020

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Dhafi Quiz

Find Answers To Your Multiple Choice Questions (MCQ) Easily at Belajar.dhafi.link. with Accurate Answer. >>

This is a List of Available Answers Options :

  1. 0.025mol/dm3
  2. 0.10mol/dm3
  3. 0.25mol/dm3
  4. 1.0mol/dm3

Click Here to See Answer

Dhafi Quiz Is an online learning educational site to provide assistance and insight to students who are in the learning stage. they will be able to easily find answers to questions at school.We strive to publish Encyclopedia quizzes that are useful for students. All facilities here are 100% Free. Hopefully, Our site can be very useful for you. Thank you for visiting.

A SOLUTION CONTAINS 1 GRAM OF SODIUM HYDROXIDE IN 250CM^3 OF SOLUTION.CALCULATE THE CONCENTRATION OF THE SOLUTION IN MOLDM^-3?

In Chemistry 2 Answers Available

Asked by mercy adeyanju on 4th July, 2020

Ask Your Own Question See More Chemistry Questions

  • Now the #"moles of solute"# are a constant. The volume of solution MAY change substantially with increasing or decreasing temperature. In some calculations #"molality"# is used in preference, which is defined by the quotient....

    #"molality"="moles of solute"/"kilograms of solvent"#

    ....this is temperature independent, and at lower concentrations, #"molarity"-="molality"#.

  • To get the molarity, you divide the moles of solute by the litres of solution.

    #"Molarity" = "moles of solute"/"litres of solution"#

    For example, a 0.25 mol/L NaOH solution contains 0.25 mol of sodium hydroxide in every litre of solution.

    To calculate the molarity of a solution, you need to know the number of moles of solute and the total volume of the solution.

    To calculate molarity:

    1. Calculate the number of moles of solute present.
    2. Calculate the number of litres of solution present.
    3. Divide the number of moles of solute by the number of litres of solution.

    EXAMPLE:

    What is the molarity of a solution prepared by dissolving 15.0 g of NaOH in enough water to make a total of 225 mL of solution?

    Solution:

    1 mol of NaOH has a mass of 40.00 g, so

    #"Moles of NaOH" = 15.0 cancel("g NaOH") × "1 mol NaOH"/(40.00 cancel("g NaOH")) = "0.375 mol NaOH"#

    #"Litres of solution" = 225 cancel("mL soln") × "1 L soln"/(1000 cancel("mL soln")) = "0.225 L soln"#

    #"Molarity" = "moles of solute"/"litres of solution" = "0.375 mol"/"0.225 L" = "1.67 mol/L"#

    Some students prefer to use a "molarity triangle".

    What is the concentration of a solution containing 1.0 g of sodium hydroxide?

    It summarizes the molarity formulas as

    #"Moles" = "molarity × litres"#

    #"Molarity" = "moles"/"litres"#

    #"Litres" = "moles"/"molarity"#