The diagonals of an isosceles trapezoid are represented by 2x+5 and x+15. what is the value of x

Answer:

1. 5x - 47 = 2x + 34

3x = 81

x = 27

A. 27

2. A=LW = 1/2 d1d2 sin angle

assume angle : ex. 48 deg

LW = 1/2 d1d2 sin 48

if d = L - 1 and d = W + 8

then : LW = 1/2 (L - 1)(W + 8) sin 48

(2LW)/sin48 = LW + 8L - W - 8

if 34 = 2(L + W)

then 17 = L + W

W = 17 - L

Substitution :

2.69 L(17 - L) = L(17 - L) + 8L - W - 8

45.73L - 2.69L² = -L² + 26L - 25

1.69L² - 19.73L - 25 = 0

by quadratic formula

L = 12. 83 or 13

W = 17 - 13 = 4

A. 4cm × 13cm

3. C. both a and b

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