How many grams of solid baso4 will form when excess na2so4 reacts with 25 ml of 0.50 m ba(no3)2?

2018-05-22T10:26:09-04:00

How many grams of solid BaSO4 will form when Na2SO4 reacts with 25mL of 0.50 M Ba(NO3)2? _Ba(NO3)2 + _Na2SO4 ---> _ BaSO4 + _ NaNO3

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2018-05-23T06:26:29-0400

Answer:1) Balance the reaction equationBa(NO3)2 + Na2SO4 ---> BaSO4 + 2 NaNO32) Calculate number of moles of Ba(NO3)2 = 0.50 moles/L x 0.025 L = 0.0125 moles3) Using stoichiometry calculate number of moles of BaSO4 =0.0125 moles4) Calculate mass of BaSO4 = 0.0125 moles x 233.4 g/mole = 2.92 g BaSO4

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