Question 11 Statistics and Probability - Exercise 13.1 Next
Answer:
Total number of outcomes favourable for event E are (1, 2, 3, 4, 5, 6) i.e., T(E) = 6 A number which is odd and less than 3 is 1 so, F(E) = 1 So, probability P(E) = F(E)/T(E) = 1/6 Hence, verifies option (a).
Was This helpful? Open in App Suggest Corrections 2 |