When a number is divided by 15, 20 or 35, each time the remainder is 8 then the smallest number is

Answered by Guest on 2018-01-20 03:45:37 | Votes 5 | #

right answer is 428

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Answered by Guest on 2018-04-09 19:24:26 | Votes 2 | #

Using Rule 5, LCM of 15, 20 and 35 = 420 \ Required least number = 420 + 8 = 428

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When a number is divided by 15, 20 or 35, each time the remainder is 8. Then the smallest number is

As we know that when a number is divided by a, b or c leaving remainders p, q and r respectively such that the difference between divisor and remainder in each case is same i.e., (a – p) = (b – q) = (c – r) = t (say) then that (least) number must be in the form of (k – t), where k is LCM of a , b and c .LCM of 15, 20 and 35 ( k ) = 420Here , remainder = 8

∴ Required least number = 420 + 8 = 428