Question 11 Statistics and Probability - Exercise 13.1
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Answer:
Total number of outcomes favourable for event E are (1, 2, 3, 4, 5, 6) i.e., T(E) = 6
A number which is odd and less than 3 is 1 so, F(E) = 1
So, probability P(E) = F(E)/T(E) = 1/6
Hence, verifies option (a).
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