Option 3 : \(\frac{1}{2}\)
Free
100 Questions 100 Marks 90 Mins
- Consider the mass of earth as ‘M’ and radius of earth ‘R’.
- Now we consider a planet twice the mass and radius of earth as 2M and 2R.
- We know the earth g = GM/R2 i.e. is g\(\; \propto \frac{M}{{{R^2}}}\) where G is Universal Gravitational Constant.
- Let g1 is acceleration due to gravity on earth and g2 is acceleration due to the gravity of another planet.
- So g2/g1 = (2M/M) × (R/2R)2
- c
- According due to gravity on surface of planet is n times of earth we get g2 = g1(n)
- Hence, the value n is ½.
Stay updated with the General Science questions & answers with Testbook. Know more about Physics and ace the concept of Gravity.
India’s #1 Learning Platform
Start Complete Exam Preparation
Daily Live MasterClasses
Practice Question Bank
Mock Tests & Quizzes
Get Started for Free Download App
Trusted by 3.4 Crore+ Students