What is the probability of getting jack or ace from a 52 card deck?

Total no. of ace in 52 cards = 4 Total no. of jack in 52 cards = 4 Therefore, Total no. of ace and jack cards out of 52 = 4 + 4 = 8

so, Prob(an Ace or A Jack) = (4C1 + 4C1)/(54C1) = 8/54 = 2/13. That's why Option 4 is correct

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you don't say if either order is OK or an ace then a jack. I will do both: 1. ORDER matters: P(ace THEN jack) = P(ace) + P(jack) so, first, there are 4 aces and 52 cards ---> P(ace) = 4/52 = 1/13. then there are 4 jacks and 51 cards --> P(jack) = 4/51 so, P(ace then jack) = 1/13 + 4/51 = 0.155 to 3dp How about P(jack then ace)?..the same numbers apply, so P=0.155 too. 2. ORDER does not matter: Now P(ace and a jack in any order) = P(ace then jack) or P(jack then ace), which is 2 times 0.155 --> 0.311 (use the full number in the calculation, not 0.155, as this is an approximate value).

jon.