What is the molarity of a solution that contains 40 g of NaOH in .50 l of solution?

Definitions

Solute-the substance being dissolved

Solvent-the substance doing the dissolving (the larger amount)

Solution- a homogeneous mixture of the solute and the solvent

Solution= solvent + solute

Aqueous (aq)= water solution

Tincture= alcohol solution

Amalgam= Mercury solution

Molarity (M)- is the molar concentration of a solution measured in moles of solute per liter of solution.

What is the molarity of a solution that contains 40 g of NaOH in .50 l of solution?

The molarity definition is based on the volume of the solution, NOT the volume of water.

Vocab. Lesson

 Incorrect= The solution is 5.0 Molarity.

Correct= The solution is 5.0 Molar.

 Example Problems

Level 1- Given moles and liters

Determine the molarity when 3.0 moles of sucrose are dissolved to make 2.0 liters of solution.

3.0 mol= X  = 1.5M solution
2.0 liters

Level 2- Given Molarity and liters of solution

 Determine the number of moles of salt dissolved in 5.0 liters of a 0.50M solution of salt water.

X mol= 0.5M solution
5.0 liters

cross multiply, X= 2.5 mols

Level 3- Given grams (instead of moles) and liters of solution

Determine the molarity when 117g of NaCl are dissolved to make 0.500 liters of solution.

   1st convert to moles, 2nd plug into the molarity equation

117g NaCl( 1mol/58.5g)= 2.00mol NaCl

2.00 mol= 4.00M solution
0.500 liters

Level 4-Given grams (instead of moles) and milliliters of solution (instead of liters)

Determine the molarity when 55.5g of CaCl2 are dissolved to make 250.mL of solution.

1st convert to moles, 2nd convert to liters, 3rd plug into the molarity equation

55.5g CaCl2( 1mol/111g)= 0.500mol CaCl2

250.ml( 1L/1000mL) =0.250L

0.500 mol= 2.00M solution
0.250 liters

Past Regents Questions-Follow link to check the answers

Jan 2003-44 What is the molarity of a solution of NaOH if 2 liters of the solution contains 4 moles of NaOH?

(1) 0.5 M     (3) 8 M
(2) 2 M       (4) 80 M

Jan. 04-41 What is the molarity of a solution containing 20 grams of NaOH in 500 milliliters of solution?

(1) 1 M (2) 2 M (3) 0.04 M (4) 0.5 M

 

Jan 2002-42 What is the molarity of a solution that contains 0.50 mole of NaOH in 0.50 liter of solution?

(1) 1.0 M      (3) 0.25 M
(2) 2.0 M      (4) 0.50 M

Aug. 2006-42 How many total moles of KNO3 must be dissolved in water to make 1.5 liters of a 2.0 M solution?

     (1) 0.50 mol     (2) 2.0 mol     (3) 3.0 mol     (4) 1.3 mol

Aug 2005-

41 What is the total number of moles of NaCl(s) needed to make 3.0 liters of a 2.0 M NaCl solution?(1) 1.0 mol      (3) 6.0 mol

(2) 0.70 mol    (4) 8.0 mol

June 2006-

16 Molarity is defined as the(1) moles of solute per kilogram of solvent(2) moles of solute per liter of solution(3) mass of a solution

(4) volume of a solvent

Aug 2008-

15 Which phrase describes the molarity of a solution?(1) liters of solute per mole of solution(2) liters of solution per mole of solution(3) moles of solute per liter of solution

(4) moles of solution per liter of solution

June 2009-46 Which sample of HCl(aq) contains the greatest number of moles of solute particles?
(1) 1.0 L of 2.0 M HCl(aq)
(2) 2.0 L of 2.0 M HCl(aq)
(3) 3.0 L of 0.50 M HCl(aq)
(4) 4.0 L of 0.50 M HCl(aq)

June 2007-

13 A 3.0 M HCl(aq) solution contains a total of(1) 3.0 grams of HCl per liter of water(2) 3.0 grams of HCl per mole of solution(3) 3.0 moles of HCl per liter of solution

(4) 3.0 moles of HCl per mole of water

June 2010-14 The molarity of an aqueous solution of NaCl is defined as the(1) grams of NaCl per liter of water(2) grams of NaCl per liter of solution(3) moles of NaCl per liter of water

(4) moles of NaCl per liter of solution

Jan 2008-

15 Which unit can be used to express solution concentration?(1) J/mol     (3) mol/L

(2) L/mol    (4) mol/s

Jan 04-41 What is the Molarity of a solution containing 20 grams of NaOH in 500 milliliters of solution?(1) 1 M      (3) 0.04 M

(2) 2 M      (4) 0.5 M

Jan 2010-40 What is the molarity of 1.5 liters of an aqueous solution that contains 52 grams of lithium fluoride, LiF, (gram-formula mass =26 grams/mole)?(1) 1.3 M    (3) 3.0 M

(2) 2.0 M    (4) 0.75 M

on to ppm or Molality

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What is the molarity of a solution that contains 40 g of NaOH in .50 l of solution?
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Answer

What is the molarity of a solution that contains 40 g of NaOH in .50 l of solution?
Verified

Hint: To calculate the concentration of the solution in terms of normality, first we need to find out the molarity of the solution. The relation between normality and molarity is that normality is equal to n-factor multiplied by the molarity.

Complete step by step answer:

Given,Volume of NaOH is 1 L.The mass of NaOH is 4.0 g.The molar mass of NaOH is 40 g/mol.The formula for calculating the number of moles is shown below.$n = \dfrac{m}{M}$Where,n is the number of moles.m is the given massM is the molar massTo calculate the number of moles of sodium hydroxide (NaOH), substitute the values of mass and molar mass in the above equation.$\Rightarrow n = \dfrac{{4.0g}}{{40g/mol}}$$\Rightarrow n = 0.1mol$The molarity of the solution is defined as the number of moles of solute dissolved in one litre of solution.The formula to calculate molarity is shown below.$M = \dfrac{n}{V}$Where,M is the molarityn is the number of molesV is the volume in litresTo calculate the molarity of the solution, substitute the values of moles and volume in the above equation.$\Rightarrow M = \dfrac{{0.1mol}}{{1L}}$$\Rightarrow M = 0.1mol/L$The normality of the solution is defined as the gram equivalent weight of the solute dissolved in one litre solution.The relation between normality of the solution and molarity of the solution is shown below.$normality = n - factor \times molarity$For any base compound, the n-factor is defined as the number of replaceable hydroxide ions present which can be replaced by 1 mole of base during the reaction.The dissociation reaction of sodium hydroxide is shown below.$NaOH \to N{a^ + } + O{H^ - }$In sodium hydroxide only one hydroxide ion is present which can be replaced. Therefore, the value of n-factor is 1.To calculate the normality, substitute the values in the equation.$\Rightarrow Normality = 1 \times 0.1$$\Rightarrow Normality = 0.1N$Thus, the concentration of the solution is 0.1N.

So, the correct answer is “Option C”.

Note:

Normality is also calculated by gram equivalent divided by the volume of solution. The gram equivalent weight is calculated by dividing molecular weight by the n-factor.