Get the answer to your homework problem.
Try Numerade free for 7 days
Boston University
q(joules) = mass(in grams)(specific heat)(change in temperature)( 3 kg = 3000 grams )q = (3000 grams)(0.44 J/gC)(25o C - 20o C)= 7 X 103 Joules===========
Mattie W. what is the final temperature of 25.0 grams of water at 22 degrees Celsius after it absorbs 259 joules of heat?
1 Expert Answer
Arturo O. answered • 09/13/18
Experienced Physics Teacher for Physics Tutoring
m = mass of water = 25.0 g
c = specific heat of water. Look it up in you textbook in units of joules/(g°C).
T1 = initial temperature = 22.0°C
T2 = final temperature = ?
Plug in the numbers and get T2 in °C.
In order to continue enjoying our site, we ask that you confirm your identity as a human. Thank you very much for your cooperation.