Three digit number which when divided by 20 30 40 50 110 in each case

20 = 1 × 2 × 2 × 5 = 22 × 51
30 = 1 × 2 × 3 × 5 = 21 × 31 × 51
40 = 1 × 2 × 2 × 2 × 5 = 23 × 51
50 = 1 × 2 × 5 × 5 = 21 × 52
LCM of 20, 30, 40 and 50 = 23 × 31 × 52 = 600∴ Required number = 600 + 10 = 610.

Hence, the least three digit number which when divided by 20, 30, 40 and 50 leaves remainder 10 in each case is 610.