Let the time period be T years. Given, P = Rs 1500, C.I. = Rs 496.50, R = 20% p.a. compounded semi-annually. Thus, the time period is 1 year 6 months. Given: P=Rs. 1,500; C.I.= Rs. 496.50 and r = 20% Then, C.I. = `"P"[( 1 + r/[2 xx 100])^(n xx 2) - 1]` ⇒ 496.50 = 1,500`[( 1 + 20/[2 xx 100])^(n xx 2) - 1]` ⇒ `[496.50]/[1500] = (11/10)^(2n) - 1` ⇒ `331/1000 + 1 = (11/10)^(2n)` ⇒ `1331/1000 = (11/10)^(2n)` ⇒ `(11/10)^3 = (11/10)^(2n)` On comparing, we get, 2n = 3 ⇒ n = `1 1/2` years |