AcademicMathematicsNCERTClass 10
Given:
Two dice are thrown simultaneously.
To do:
We have to find the probability of getting a doublet.
Solution:
When two dice are thrown, the total possible outcomes are $6\times6=36$.
This implies,
The total number of possible outcomes $n=36$
Outcomes where we get a doublet are $[( 1,\ 1),\ ( 2,\ 2),\ ( 3,\ 3),\ ( 4,\ 4),\ ( 5,\ 5),\ ( 6,\ 6)]$
Total number of favourable outcomes $=6$
Probability of an event $=\frac{Number\ of\ favourable\ outcomes}{Total\ number\ of\ possible\ outcomes}$
Therefore,
Probability of getting a doublet $=\frac{6}{36}$
$=\frac{1}{6}$
The probability of getting a doublet is $\frac{1}{6}$.
Updated on 10-Oct-2022 10:55:29
Answer: Option 1
In a simultaneous throw of dice, n (S) = (6 × 6) = 36 Let E = event of getting a doublet = [(1, 1), (2, 2), (3, 3), (4, 4), (5, 5), (6, 6)] ∴ P(E) = $$\frac{{n (E)}}{{n (S)}}$$ = $$\frac{{6}}{{36}}$$ = $$\frac{{1}}{{6}}$$
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