Question 6 Exercise 8(C)
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Answer:
Solution 6:
The least number which is exactly divisible by each given number is their LCM
Required number is LCM of 12, 15, 18, 24 and 36.
LCM = least required number = 2\times2\times3\times3\times5\times2=360
Hence, required number = 360
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Find the smallest number which, when divided by 12, 15, 18, 24 and 36 leaves no remainder
The least number which is exactly divisible by each given number is their L.C.M. Required number L.C.M. of 12, 15, 18, 24 and 36.
| 2 | 12, | 15, | 18, | 24, | 36 |
| 2 | 6, | 15, | 9, | 12, | 18 |
| 3 | 3, | 15, | 9, | 6, | 9 |
| 3 | 1, | 5, | 3, | 2, | 3 |
| 1, | 5, | 1, | 2, | 1 |
∴ L.C.M. = Least required number
= 2 x 2 x 3 x 3 x 5 x 2 = 360
Hence, the least required number = 360
Concept: Property HCF x LCM = Product of Two Numbers
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