At what altitude above earths surface is the acceleration due to gravity equal to g/4

At what altitude above the Earth's surface is the acceleration due to gravity equal to g/3?

Homework Equations

The Attempt at a Solution

but it is saying this is not correct

At what altitude above the Earth's surface is the acceleration due to gravity equal to g/3?

Homework Equations

ag=G Me/(Re+H)^2

The Attempt at a Solution

I solved for H and got H=√3 Re-Re using this i got 17*10^6

but it is saying this is not correct

I solved for H and got H=√3 Re-Re
using this i got 17*10^6

for re i used 6.37*10^6m the answer is also sopossed to be in meters i started with ag=g Me/(Re+H)^2 then plugged in 1/3*9.8=G Me/(Re+H)^2 I reduced that to ag=1/(Re+H)^2=1/3(1/Re^2) from there i got (Re+H)^2=3Re^2 Re+H=sqrt(3)*Re

H=sqrt(3)Re-Re

Your derivation looks okay, so you must be having finger problems with the calculator