You haven't indicated whether or not this is a REGULAR polygon (one whose sides are all of equal length) but I'll assume that it is. You can start with the formula for the sum of the interior angles (S) of a regular polygon of n-sides:
 Divide both sides by 180 Add 2 to both sides. The regular polygon has 10 sides. This is known as a decagon.
Question 3 Exercise 28(A) Next
Answer:
Solution: (i) 1440° Let no of sides = n Sum of interior angles of polygon =1440° (2n - 4) x 90° = 1440° 2n - 4 = 1440°/90° n - 2 = 8 n = 10 (ii) 1620° Let no of sides = n Sum of interior angles of polygon =1620° (2n - 4) x 90° = 1440° 2n - 4 = 1440°/90° n - 2 = 9 n = 11
Video transcript "Hello. We're going to see a number of sides of the polygon. The sum of the interior angles is fundable 4-0 in turning. This is wonderful for zero. The the first one we are going to see later. I will say the next second 1 x 2 so we know the form 1 to n minus 4/9 equal to 1 double Force then here you can do it as 2 N minus four is equal to one level 4 0 double for 0.98. So n minus 2 is equal to 3/8 here directly in the whole street. So they deserve is 10 sides here. So it's going to be interior angles are possible for one down for system. So it's a great event in size for this one. Next one 1620 machine is 1620 should be the same thing. Like the first one we did okay to n minus 4 into 90 is gonna be a 1620. Okay, now we check it out to 8 minus 4 equal to 1 6 2 0 divided by 90. So when you do this you're gonna get n minus 2 is equal to 9. So here we get n is equal to 2 sighs. Thank you for watching. Our video 11 sites are in is called to live inside. So the final answer is 11 times. Thank you for watching our video. If you have any queries, please let me know in the comment section. "
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Find the number of sides of a polygon the sum of whose interior angle is 1440
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